Candy Distribution Game Algorithm
- Login to Download
- 1 Credits
Resource Overview
A circular candy distribution simulation involving 5 children numbered 1-5, where each child divides their candies into three equal parts (eating any leftovers) and distributes two parts to adjacent neighbors. This document explains the algorithm and provides implementation insights for simulating the redistribution process.
Detailed Documentation
In a kindergarten scenario, five children numbered 1 through 5 form a circle to play a candy distribution game. Each child starts with a certain number of candies. The game begins with child 1 dividing their candies into three equal portions (immediately consuming any remainder), keeping one portion for themselves, and distributing the other two portions to their immediate neighbors. The process continues sequentially with children 2, 3, 4, and 5 following the same procedure. After one complete round, each child ends up with a different quantity of candies.
From an implementation perspective, child 1's candy count is calculated using integer division: original_candies // 3. Any remainder (original_candies % 3) is consumed immediately. For example, if child 1 starts with 4 candies, the algorithm would:
1. Calculate portion size: 4 // 3 = 1
2. Determine remainder: 4 % 3 = 1 (eaten)
3. Distribute: keeps 1, gives 1 to child 2 and 1 to child 5
4. Final count: 1 candy remaining
Child 2 follows the same algorithmic process. Starting with 3 candies:
1. Portion calculation: 3 // 3 = 1
2. Remainder: 3 % 3 = 0 (no consumption)
3. Distribution: keeps 1, gives 1 to child 1 and 1 to child 3
4. Final count: 1 candy remaining
The simulation uses modular arithmetic to handle the circular arrangement (children 1 and 5 are adjacent). Key programming components would include:
- An array to track candy counts for each child
- A loop iterating through each child's turn
- Integer division and modulus operations for portion calculation
- Neighbor indexing using modulo 5 arithmetic for circular distribution
After one complete iteration through all five children using this algorithm, the final candy distribution results in each child possessing 2 candies. The implementation would need to handle sequential updates where each child's distribution affects their neighbors' counts before the next child's turn.
- Login to Download
- 1 Credits